**Freaky game**

muslimah-2k8

muslimah-2k8

Junior Member
What is the trick?

If you want to find out how it works on your own, don't read this.....

Fun-dampener........

The trick to the game is that the gopher uses the same symbol for every multiple of 9, from 0 through 81 (it is impossible to get a higher number using only two digits). The gopher assigns the same symbol to the multiples of 9 as to other non-multiples of 9 in order to cover up the trick; the symbol picked for each game is randomized. No matter which two-digit integer the player chooses, when the subtraction is done, the resulting number will always be a multiple of 9. In fact, no matter which (nonnegative) integer the player chooses, the result will always be a multiple of 9. The former can be proven using elementary algebra.

Proof for 2 digits

Let n be a 2-digit integer. Additionally, let a be the first digit of n and b be the second digit of n. Finally, let c equal the sum of the digits of n, so c = a + b..

An equivalent form for n, by virtue of using a decimal numeral system, is n = 10a + b.

The resulting number, z, is given by z = n − c = (10a + b) − (a + b) = 9a. Hence, z is always a multiple of 9.
 
muslim56

muslim56

Human Being
I get it know!
say you had the number 53 and your figure is this:Figure 1 so you wouldn`t get the gopher`s "figure"but if you took for example the number 45 and your figure was this: Figure 2 and the gopher`s "figure"would be exactly your figure. This is how the game works.
 
Sakib

Sakib

♣♦Sakib♦♣
and each time u "press try again" it changes the symbol so u think its a new symbol but its still the same thing....:lol:

:salam2:
 
whitecat

whitecat

Junior Member
:wasalam:
muslimah-2k8 said:
If you want to find out how it works on your own, don't read this.....

Fun-dampener........

The trick to the game is that the gopher uses the same symbol for every multiple of 9, from 0 through 81 (it is impossible to get a higher number using only two digits). The gopher assigns the same symbol to the multiples of 9 as to other non-multiples of 9 in order to cover up the trick; the symbol picked for each game is randomized. No matter which two-digit integer the player chooses, when the subtraction is done, the resulting number will always be a multiple of 9. In fact, no matter which (nonnegative) integer the player chooses, the result will always be a multiple of 9. The former can be proven using elementary algebra.

Proof for 2 digits

Let n be a 2-digit integer. Additionally, let a be the first digit of n and b be the second digit of n. Finally, let c equal the sum of the digits of n, so c = a + b..

An equivalent form for n, by virtue of using a decimal numeral system, is n = 10a + b.

The resulting number, z, is given by z = n − c = (10a + b) − (a + b) = 9a. Hence, z is always a multiple of 9.
Click to expand...

:salam2:
thnx for tellin the trick..it ws really freaking me out..
 
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