We love math

[rayray]

OMG! you guys are GEEKS!

but I mean that in a loving way...

 

[rayray]

the first term of my sequence is
1
ie: we have in the first term One 1
if we replace One by 1 we obtain the second term 11
11
with the same way,11= two 1,we replace Two by its figure 2 then we obtain th 3th term ..etc
21
1211
111221
312211
the next one???????
312211=One 3 One 1 Two 2 Two one ; which becomes

13112221

I don't get it..... so you were counting the number of times the number appeared? huh?... why is the third term..1?

hmm..ok just answer this. how did you get 1211 (third line)

 

[arzafar]

I don't get it..... so you were counting the number of times the number appeared? huh?... why is the third term..1?

hmm..ok just answer this. how did you get 1211 (third line)

well it's just an innovative way of counting.

1 = one 1 so next term is 11
11 = two 1 so next term is 21
21 = one 2 one 1 so next term is 1211
and so on

btw below this is the current problem.

A customer hands a cigar clerk a 5-dollar bill for two dollars' worth of cigars. The latter has no change, but gets some next door from a drug clerk, who gives him five 1-dollar bills for the 5-dollar bill. The customer leaves with the cigars and three dollars change. An hour later, the drug clerk rushes in, saying the 5-dollar bill was counterfeit. The cigar clerk gives him a good 5-dollar bill. How much did the cigar clerk lose in money and cigar?

 

[True_Sultan]

well it's just an innovative way of counting.

1 = one 1 so next term is 11
11 = two 1 so next term is 21
21 = one 2 one 1 so next term is 1211
and so on

btw below this is the current problem.

A customer hands a cigar clerk a 5-dollar bill for two dollars' worth of cigars. The latter has no change, but gets some next door from a drug clerk, who gives him five 1-dollar bills for the 5-dollar bill. The customer leaves with the cigars and three dollars change. An hour later, the drug clerk rushes in, saying the 5-dollar bill was counterfeit. The cigar clerk gives him a good 5-dollar bill. How much did the cigar clerk lose in money and cigar?

I know its a trick question but the cigar clerk lost only 3 dollars I believe and 1 cigar..a guess

 

[Al-Kashmiri]

As-salaamu `alaykum

How about we cut down on the riddles and look at real mind-boggling problems. Who here is familiar with combinations & permutations?

 

[rayray]

As-salaamu `alaykum

How about we cut down on the riddles and look at real mind-boggling problems. Who here is familiar with combinations & permutations?

post one!

 

[rayray]

well it's just an innovative way of counting.

1 = one 1 so next term is 11
11 = two 1 so next term is 21
21 = one 2 one 1 so next term is 1211
and so on

btw below this is the current problem.

A customer hands a cigar clerk a 5-dollar bill for two dollars' worth of cigars. The latter has no change, but gets some next door from a drug clerk, who gives him five 1-dollar bills for the 5-dollar bill. The customer leaves with the cigars and three dollars change. An hour later, the drug clerk rushes in, saying the 5-dollar bill was counterfeit. The cigar clerk gives him a good 5-dollar bill. How much did the cigar clerk lose in money and cigar?

ahhhhh! lol!

 

[arzafar]

c'mon, that was a simple question and its not a riddle!!!

 

[arzafar]

Ok the clerk lost a total of $5.
$2 in cigars
$3 in cash.

 

[arzafar]

The blank in the equation below represents a 3-digit number and A is a digit from 1 to 9.

___ - AA = AA

Provide 3 possible values that may be filled in the blank.

 

[hayat84]

I would like to take part me too to this amusing game,but unforunatelly I wasn't good in math:I had 4!

 

[jahid89]

The blank in the equation below represents a 3-digit number and A is a digit from 1 to 9.

___ - AA = AA

Provide 3 possible values that may be filled in the blank.

let A=9
???-AA=AA
then 3 digit will be 198 bcoz
198 -99=99

 

[arzafar]

I would like to take part me too to this amusing game,but unforunatelly I wasn't good in math:I had 4!

ok we'll wait for the rest to try this question. then ill explain the answer.

 

[arzafar]

So, what we have here is

x>=100,
x<=999 and
x - 10*y+y = 10*y+y, where 1<=y<=9. Find x.

So,
x = 22y.
Since x>=100, y>=Roundup(100/22) >= 5
And since x<=999, y<=Rounddown(999/22) <= 45, which is redundant since y<=9.
Thus y=5,6,7,8 or 9.

To illustrate:

y=1 -> x=22 invalid because two-digit
y=2 -> x=44 invalid because two-digit
y=3 -> x=66 invalid because two-digit
y=4 -> x=88 invalid because two-digit
y=5 -> x=110 works
y=6 -> x=132 works
y=7 -> x=154 works
y=8 -> x=176 works
y=9 -> x=198 works

So there are five possible values: 110, 132, 154, 176 or 198.

nice!
now post another problem

 

[Abdullah6]

8d2-3d-8

 

[arzafar]

8d2-3d-8

where is the question?

 

[arzafar]

ok here is another one

A painter needed 3 days to paint the walls of a room. how long would it take him, working at the same rate, to paint a room twice as long, twice as wide and twice as high?

 

[jahid89]

ok here is another one

A painter needed 3 days to paint the walls of a room. how long would it take him, working at the same rate, to paint a room twice as long, twice as wide and twice as high?

let lenght=x, breadth=y, height=z
area1=2(xy+yz+zx)=3
according to question
x=2x, y=2y,z=2z

so area2=2(4xy+4yz+4zx)
area2=8(xy+yz+zx)
area2=4*3
area2=12
=12 days

 

[arzafar]

let lenght=x, breadth=y, height=z
area1=2(xy+yz+zx)=3
according to question
x=2x, y=2y,z=2z

so area2=2(4xy+4yz+4zx)
area2=8(xy+yz+zx)
area2=4*3
area2=12
=12 days

correct!
now comes the difficult part
post another problem.

 

[jahid89]

what is the limit of y when y-> -3+ (y^5 - y^3)/((y^2) -9)?
when y tends to -3 by the right....